206. 反转链表

Problem

给你单链表的头节点 head ,请你反转链表,并返回反转后的链表

示例 1:

输入:head = [1,2,3,4,5]
输出:[5,4,3,2,1]

示例2:

输入:head = [1,2]
输出:[2,1]

示例3:

输入:head = []
输出:[]

提示:

  • 链表中节点的数目范围是 [0, 5000]

  • -5000 <= Node.val <= 5000

Solution

func reverseList(head *ListNode) *ListNode {
    cur := head
    var pre, next *ListNode

    for cur != nil {
        next = cur.Next
        cur.Next = pre 
        pre = cur 
        cur = next
    }
    return pre
}

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