1795. 每个产品在不同商店的价格

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1795. 每个产品在不同商店的价格 - 力扣（LeetCode）力扣 LeetCode

Problem

请你重构 Products 表，查询每个产品在不同商店的价格，使得输出的格式变为(product_id, store, price) 。如果这一产品在商店里没有出售，则不输出这一行。

输出结果表中的 顺序不作要求 。

查询输出格式请参考下面示例。

示例 1：

输入：
Products table:
+------------+--------+--------+--------+
| product_id | store1 | store2 | store3 |
+------------+--------+--------+--------+
| 0          | 95     | 100    | 105    |
| 1          | 70     | null   | 80     |
+------------+--------+--------+--------+
输出：
+------------+--------+-------+
| product_id | store  | price |
+------------+--------+-------+
| 0          | store1 | 95    |
| 0          | store2 | 100   |
| 0          | store3 | 105   |
| 1          | store1 | 70    |
| 1          | store3 | 80    |
+------------+--------+-------+
解释：
产品0在store1，store2,store3的价格分别为95,100,105。
产品1在store1，store3的价格分别为70,80。在store2无法买到。

Solution

MySQL

# Write your MySQL query statement below
select product_id, 'store1' as store, store1 as price
from Products where store1 is not null
union all 
select product_id, 'store2' as store, store2 as price
from Products where store2 is not null
union all
select product_id, 'store3' as store, store3 as price
from Products where store3 is not null

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